Statistik-Laborkernsmoothlatticemassmvanlmenlsspatialforeignmodregstepfunctesttsbootclass3n=5003
i<-c(1:n)
FensterAuto<-ceiling(runif(i,0,3))
Wahl1<-ceiling(runif(i,0,3))
Wahl3<-Wahl1
T1<-as.numeric(FensterAuto==Wahl3)
T1<-cumsum(T1)/i
T2<-1-T1
1{\rtf1\ansi\ansicpg1252\deff0\deflang1031{\fonttbl{\f0\fswiss\fprq2\fcharset0 Verdana;}{\f1\froman\fcharset0 Times New Roman;}{\f2\fnil\fcharset0 Courier New;}{\f3\fnil Courier New;}}
{\colortbl ;\red0\green0\blue0;}
\viewkind4\uc1\pard\cf1\f0\fs20 The Car/Goat Problem.
\par \cf0 Statistical Lab determines the chances of winning the 'goat problem' for two different strategies by simulating the game.
\par At the end of a TV-show, the player has to choose one of three gates. behind one of these gates is a car and behind the other gates is a goat.
\par
\par After the player chooses one gate the showmaster gives him a new chance. the showmaster opens one gate with a goat. Now, the player has the chance to change his first choice.
\par The question is: Should he change his choice or should he stay at his first choice?
\par Is the chance to win the car increasing, staying at one level or even decreasing, after changing the choice?\f1\fs24
\par \cf1\f2\fs16 \f3
\par }
2{\rtf1\ansi\ansicpg1252\deff0\deflang1031{\fonttbl{\f0\fswiss\fprq2\fcharset0 Arial;}{\f1\fnil Courier New;}}
{\colortbl ;\red0\green0\blue0;}
\viewkind4\uc1\pard\cf1\b\f0\fs20 Legend: Red = Strategy 1 (never changing the choice)
\par Blue = Strategy 2 (always changing the choice)
\par \b0\f1\fs16
\par }
The Goat/CarThe chance to win{\rtf1\ansi\ansicpg1252\deff0{\fonttbl{\f0\fnil\fcharset0 MS Sans Serif;}}
{\colortbl ;\red0\green0\blue0;}
\viewkind4\uc1\pard\cf1\lang1031\f0\fs20
\par }